Given : Total number of questions = 6
The probability of getting success= 0.20
Binomial probability distribution :-
[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex], where P(X) is probability of getting success in x trials, n is the total number of trials and p is the probability of success in each trial ( in decimal ).
Now, the probability of no correct answers :-
[tex]P(x)=^6C_0(0.2)^0(0.8)^{6}\\\\=(0.8)^{6}\\\\=0.262144[/tex]
Hence, the required probability = 0.262144
