Answer:
The money invested in the account 1 was $25,000 and in the account 2 was 5,000.
Step-by-step explanation:
In this case we can formulate a system of equations that could find the amount invested in each account, this is:
Money invested in the account 1 is A
Money invested in the account 2 is B
Eq. 1: [tex]A+B=30,000[/tex]
Eq. 2: [tex]\frac{9}{100} *A+\frac{6}{100} *B=1,950[/tex]
Replacing the equation 1 in 2, this is:
[tex]\frac{9}{100} *(30,000-B)+\frac{6}{100} *B=1,950
Clearing the value of B:
[tex]2,700-0.09B+0.06B=1,950[/tex]
[tex]2,700-1,950=0.09B-0.06B[/tex]
[tex]750=0.03B[/tex]
[tex]B=\frac{750}{0.03}[/tex]
[tex]B=25,000[/tex]
Now, we can find A:
[tex]A=30,000-B\\A=30,000-25,000\\A=5,000[/tex]
The money invested in the account 1 was $5,000 and in the account 2 was 25,000.
