A scalloped hammerhead shark swims at a steady speed of 1.7 m/s with its 89-cm-wide head perpendicular to the earth's 52 μT magnetic field. You may want to review (Pages 806 - 809) . Part A What is the magnitude of the emf induced between the two sides of the shark's head

Respuesta :

Answer:

The magnitude of the emf induced between the two sides of the shark's head is [tex]7.87\times10^{-5}\ V[/tex]

Explanation:

Given that,

Steady speed = 1.7 m/s

Wide = 89 cm

Magnetic field = 52\mu T

We need to calculate the emf induced

Using formula of induced emf

[tex]\epsilon = Blv[/tex]

Where, B = magnetic filed

l = length

v = speed

[tex]\theta=90^{\circ}[/tex]

[tex]\sin90=1[/tex]

Put the value into the formula

[tex]\epsilon=52\times10^{-6}\times89\times10^{-2}\times1.7[/tex]

[tex]\epsilon=7.87\times10^{-5}\ V[/tex]

Hence,  The magnitude of the emf induced between the two sides of the shark's head is [tex]7.87\times10^{-5}\ V[/tex]