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As an aid to the establishment of personnel requirements, the director of a hospital wishes to estimate the mean number of people who are admitted to the emergency room during a 24 hour period. The director randomly selects 64 different 24-hour periods and determines the number of admissions for each. For this sample, he calculated a mean a 396 and a standard deviation of 100. The 95% confidence interval results in an interval of 396 +/- 24.9793. Identify the sampling error or margin of error.

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JeanaShupp

Answer: 24.9793

Step-by-step explanation:

Given : The director randomly selects 64 different 24-hour periods and determines the number of admissions for each.

For this sample, he calculated a mean  [tex]\overlien{x}=396[/tex] and a standard deviation of 100.

The 95% confidence interval results in an interval of [tex]396 \pm 24.9793[/tex]

We know that the confidence interval for population mean is given by :_

[tex]\overlien{x}\pm E[/tex], where E is the margin of error.

By comparing this to the given interval , we find that the margin of error = 24.9793

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