Answer:
Rotational kinetic energy of the forearm is 412.33 J.
Explanation:
It is given that,
The linear velocity of the ball relative to the elbow joint is, v = 19.9 m/s
Distance from the joint, r = 0.49 m
Moment of inertia of the forearm, I = 0.5 kg/m²
We need to find the rotational kinetic energy of the forearm. It is given by :
[tex]E=\dfrac{1}{2}I\omega^2[/tex]
[tex]\omega[/tex] is the angular speed, [tex]\omega=\dfrac{v}{r}[/tex]
[tex]E=\dfrac{1}{2}\times 0.5\ kg/m^2\times (\dfrac{19.9\ m/s}{0.49\ m})^2[/tex]
E = 412.33 J
So, the rotational kinetic energy of the forearm is 412.33 J. Hence this is the required solution.
