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A ballistic pendulum consists of a 3.60 kg wooden block on the end of a long string. From the pivot point to the center‐of‐mass of the block is a distance of 2.80 m. With the pendulum hanging straight down, a rifle bullet of 28.0 g mass moving with a speed of 210 m/s embeds itself into the wood. To what maximum angle does the pendulum (with embedded bullet) swing upward?

Respuesta :

Answer:

17.799°

Explanation:

When the bullet hits the block at that time the momentum is conserved

So, initial momentum = final momentum

[tex]P_i=P_f[/tex]

So [tex]28\times 10^{-3}\times 210=(3.6+0.028)v_f[/tex]

[tex]v_f=1.6207\ m/sec[/tex]

Now energy is also conserved

So [tex]\frac{1}{2}\times (3.6+0.028)\times 1.6207^2=(3.6+0.028)\times 9.81\times 2.8(1-cos\Theta )[/tex]

[tex]cos\Theta =0.8521So\ \Theta =17.799^{\circ}[/tex]

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