Answer:
(sqrt(2),45°)
Step-by-step explanation:
because norm of(1,1)=sqrt(1^2+1^2)=sqrt(2)
angle=arctan(1/1)=45°
Answer:
(√2,45°)
Step-by-step explanation:
Here you are required to convert (x,y) to (r,Ф)
[tex]r=\sqrt{x^2+y^2}[/tex]
Ф= tan⁻¹ (y/x)
Given x=1 and y=1
[tex]r=\sqrt{1^2+1^2} \\\\\\r=\sqrt{1+1} =\sqrt{2}[/tex]
(1,1) is in the 1st quadrant thus Ф should be in the 1st quadrant too
Ф=tan⁻¹ (1) =45°
Hence (1,1) in polar form is (√2,45°)
