It is question number 32 is am looking for please help thanks

Answer:
The answer for this question is : 64cm²
Step-by-step explanation:
Firstly, Let the side of the square be "x"
When the paper is folded the resultant rectangle will have the same length as the side of the square and the width 1/2 of the square side.
So perimeter of the rectangle is :
[tex]x[/tex]+ [tex]\frac{x}{2}[/tex] + [tex]x[/tex] + [tex]\frac{x}{2}[/tex]
[tex]3x[/tex] = [tex]24[/tex]
[tex]x = 8[/tex]
[tex]x^{2} = 24cm[/tex]²
The area of the original paper is 8 × 8 = 64cm²
Answer:
64 cm²
Step-by-step explanation:
When a square is folded in half the resultant shape is a rectangle
With length equal to the side of the square and width half the side of the square.
let the length be x then the width is 0.5x
Form an equation and solve for x
x + x + 0.5x + 0.5x = 24 ← Perimeter of rectangle
3x = 24 ( divide both sides by 3 )
x = 8
Thus the side of the original square is 8 cm and
area = 8 × 8 = 64 cm²