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If i have a kinematic equation vf^2=vi^2-2*a(xf-xi), how can i solve for xi step by step

Respuesta :

Answer:

Explanation:

[tex]v_f^2 = v_i^2-2a(x_f-x_i)[/tex]

Subtract both sides by [tex]v_i^2[/tex]:

[tex]- v_i^2+v_f^2 = -2a(x_f-x_i)[/tex]

Divide both sides by -2*a:

[tex]\frac{v_i^2 - v_f^2}{2a} =x_f-x_i[/tex]

Add both sides by [tex]x_i[/tex]:

[tex]x_i+\frac{v_i^2 - v_f^2}{2a} =x_f[/tex]

Subtract both sides by [tex]\frac{v_i^2 - v_f^2}{2a}[/tex]:

[tex]x_i=x_f-\frac{v_i^2 - v_f^2}{2a}[/tex]