Answer:
Total 9 students are in only one of the two clubs.
Step-by-step explanation:
A : Student in the chess club.
B : Student in bridge club.
Total number of students, S=36
Total students in chess club, n(A)=10
Total students in bridge club, n(B)=13
Students are not in either club [tex]n(A\cup B)'=20[/tex]
Number of students are in either chess club or bridge club is
[tex]n(A\cup B)=S-n(A\cup B)'=36-20=16[/tex]
Total number of student in both clubs.
[tex]n(A\cap B)=n(A)+n(B)-n(A\cup B)=10+13-16=7[/tex]
Students only in chess club,
[tex]n(A\cap B')=n(A)-n(A\cap B)=10-7=3[/tex]
Students only in bridge club,
[tex]n(A'\cap B)=n(B)-n(A\cap B)=13-7=6[/tex]
Total students that are in only one of the two clubs,
[tex]T=3+6=9[/tex]
Therefore, total 9 students are in only one of the two clubs.
