Answer:
The set with greater numbers is greater than the other set by 12 units.
Step-by-step explanation:
Let us call [tex]A_1[/tex] the set with the smaller numbers and [tex]A_2[/tex] the other one. Each set has 4 consecutive positive integers and on integer in common. Then:
[tex]A_1= \{a,a+1,a+2,a+3\}\\A_2=\{a+3,a+4,a+5,a+6\}[/tex]
The sum of all the numbers in A1 is:
[tex]Sum_1=a+a+1+a+2+a+3=4a+6[/tex]
The sum of all number in A2 is:
[tex]Sum_2=a+3+a+4+a+5+a+6=4a+18[/tex]
The differenc betwen the two sets is:
[tex]R=4a+18-(4a+6)=4a+18-4a-6=18-6=12[/tex]
The set A2, the one with the grater numbers, is greater than the set A1 by 12 units.
