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If n=28, ¯ x (x-bar)=50, and s=5, construct a confidence interval at a 99% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.

Respuesta :

Answer:

Step-by-step explanation:

Given that

n=28, ¯ x (x-bar)=50, and s=5

Here only sample std deviation is known, hence we can use only t critical value

df =n-1 =27

t critical = 2.05

Margin of error = [tex]2.05 *\frac{s}{\sqrt{n} } \\=1.937[/tex]

Confidence interval = 28±1.937

=(26.1, 29,9)

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