Answer: 0.2401
Step-by-step explanation:
Given : A baseball player comes to bat 4 times in a game
The probability that a strike-out for this player= 0.30
The binomial probability distribution :-
[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex], where P(X) is the probability of getting success in x trials, n is the total number of trials and p is the probability of success in each trial ( in decimal ).
Now, the probability that the player does not strike out for the entire game :-
[tex]P(x)=^4C_0(0.3)^0(0.7)^{4}\\\\=(0.7)^{4}\\\\=0.2401[/tex]
Hence, the required probability = 0.2401
