Answer:
The velocity relative to the surface of the ice is 6.5 m/s.
Explanation:
Given that,
Mass of girl m= 45.0 kg
Mass of plank M= 150 kg
Velocity = 1.50 m/s
We need to calculate the velocity relative to the surface of the ice
Using conservation of momentum
[tex]mv_{1}+Mv_{2}=(m+M)v[/tex]
Here, [tex]v_{2}=0[/tex] because plank at rest
[tex]v_{1}=\dfrac{m+M}{m}\times v[/tex]
Put the value into the formula
[tex]v_{1}=\dfrac{45+150}{45}\times1.50[/tex]
[tex]v_{1}=6.5\ m/s[/tex]
Hence, The velocity relative to the surface of the ice is 6.5 m/s.
