Respuesta :
Explanation:
It is given that,
Speed, v₁ = 7.7 m/s
We need to find the velocity after it has risen 1 meter above the lowest point. Let it is given by v₂. Using the conservation of energy as :
[tex]\dfrac{1}{2}mv_1^2=\dfrac{1}{2}mv_2^2+mgh[/tex]
[tex]v_2^2=v_1^2-2gh[/tex]
[tex]v_2^2=(7.7)^2-2\times 10\times 1[/tex]
[tex]v_2=6.26\ m/s[/tex]
So, the velocity after it has risen 1 meter above the lowest point is 6.26 m/s. Hence, this is the required solution.
Answer:
Explanation:
It is given that,
Speed, v₁ = 7.7 m/s
We need to find the velocity after it has risen 1 meter above the lowest point. Let it is given by v₂. Using the conservation of energy as :
So, the velocity after it has risen 1 meter above the lowest point is 6.26 m/s. Hence, this is the required solution.