Answer:
Graph A : Lower bound is
x=1
y=-3
Graph B : Upper Bound is
x=2
y=2
Solution is : (2,1)
Step-by-step explanation:
Function 1
f(x) = x^2-3
y=x^2-3
Adding 3 on both sides we get
y+3=x^2
comparing it with the standard form of Parabola (x-a)^2=(y-b) , it represents the parabola opening up and having origin at (0,-3). Let us draw the parabola opening up and having origin (0,-3)
Function 2
g(x)=sqrt(x-1)
y=sqrt(x-1)
y^2=x-1
comparing it with the standard form of Parabola (y-a)^2=(x-b) , it represents the parabola opening right and having origin at (1,0). Let us draw the parabola opening up and having origin (1,0)
It represents the parabola opening to the right but only in 1st quadrant as y can not be less than 0.
As we see the graph in the attached image , the point at which two intersects is (2,1) . hence the solution to the above graphs is(2,1)
Please refer to the attached image
