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A roller of radius 14.25 cm turns at 10 revolutions per second. What is the linear velocity of the roller in meters per second?

Respuesta :

LammettHash

A point on the edge of the roller travels the circumference of the roller in 1 revolution, so that its linear velocity is

(10 rev/s) * (2*(14.25 cm)*pi cm/rev) = 285 pi cm/s

or about 895.4 cm/s.

Answer:

Linear velocity, v = 8.95 m/s

Step-by-step explanation:

It is given that,

Radius of the roller, r = 14.25 cm = 0.1425 m

Angular velocity, [tex]\omega=10\ rev/s=62.83\ rad/s[/tex]

We need to find the linear velocity of the roller. Th linear velocity of the roller is given by :

[tex]v=r\times \omega[/tex]

[tex]v=0.1425\times 62.83[/tex]

v = 8.95 m/s

So, the linear velocity of the roller is 8.95 m/s. Hence, this is the required solution.

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