Answer:
Step-by-step explanation:
[tex]x^2-6x-7=0\\\\x^2+x-7x-7=0\\\\x(x+1)-7(x+1)=0\\\\(x+1)(x-7)=0\iff x+1=0\ \vee\ x-7=0\\\\x+1=0\qquad\text{subtract 1 from both sides}\\\bold{x=-1}\\\\x-7=0\qquad\text{add 7 to both sides}\\\bold{x=7}[/tex]
Answer:
x = - 1, x = 7
Step-by-step explanation:
Given
x² - 6x - 7 = 0
Consider the factors of the constant term (- 7 ) which sum to give the coefficient of the x- term
The factors are - 7 and + 1, since
- 7 × 1 = - 7 and - 7 + 1 = - 6, hence
(x - 7)(x + 1) = 0
Equate each factor to zero and solve for x
x - 7 = 0 ⇒ x = 7
x + 1 = 0 ⇒ x = - 1
