Answer:
No, there are not enough Ba atoms
Explanation:
Mass of [tex]2.50cm^{3}[/tex] of Ba = [tex](2.50\times 3.51)g=8.775g[/tex]
Mass of [tex]1.75cm^{3}[/tex] of S = [tex](1.75\times 2.07)g=3.6225g[/tex]
Molar mass of Ba = 137.33 g
Molar mass of S = 32.06 g
1 mol of an element contains [tex]6.023\times 10^{23}[/tex] number of atoms.
So 8.775 g of Ba = [tex]\frac{8.775\times 6.023\times 10^{23}}{137.33}atoms=3.85\times 10^{22}atoms[/tex]
So 3.6225 g of S = [tex]\frac{3.6225\times 6.023\times 10^{23}}{32.06}atoms=6.81\times 10^{22}atoms[/tex]
As 1 atom of Ba reacts with 1 atom of S therefore enough Ba atoms are not present for reaction.
