Answer:
a)The mass percentages of nitrogen and phosphorus in the compound is 24.34% and 26.95% respectively.
b) 14.78 grams ammonia is incorporated into 100. g of compound.
Explanation:
a) Ammonium dihydrogen phosphate that is [tex]NH_6PO_4[/tex].
Molecular mass of ammonium dihydrogen phosphate = M
M = 115 g/mol
Percentage of an element in a compound:
[tex]\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100[/tex]
Percentage of nitrogen:
[tex]\frac{1\times 28 g/mol}{115 g/mol}\times 100=24.34\%[/tex]
Percentage of phosphorus:
[tex]\frac{1\times 31g/mol}{115 g/mol}\times 100=26.95\%[/tex]
b) Percentage of ammonia in 1 molecule of ammonium dihydrogen phosphate.
Molar mass of ammonia = 17 g/mol
[tex]\%=\frac{17 g/mol}{115 g/mol}\times 100=14.78\%[/tex]
Amount of ammonia in 100 grams of compound:
14.78% of 100 g of ammonium dihydrogen phosphate:
[tex]\frac{14.78}{100}\times 100 g=14.78 g[/tex]
14.78 grams ammonia is incorporated into 100. g of compound.