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A cold-drawn AISI 1015 steel tube is 300 mm OD by 200 mm ID and is to be subjected to an external pressure caused by a shrink fit. What maximum pressure would cause the material of the tube to yield?. Syt = Syc = 600 MPa.

Respuesta :

Answer:

The maximum pressure= 230.76 M Pa

Explanation:

Given that

Outer diameter=300 mm

Inner diameter=200 mm

Condition for thick cylinder:

    If thickness of cylinder is greater than 1/20 times of internal diameter,Then it is called thick cylinder.

We know that when thick cylinder is subjected to external pressure ,the hoop stress given as

[tex]\sigma _h=-P\times \dfrac{R_0^2+R_i^2}{R_0^2-R_i^2}[/tex]

Now by putting values

[tex]\sigma _h=-P\times \dfrac{150^2+100^2}{150^2-100^2}[/tex]

[tex]\sigma _h=-2.6 P[/tex]

For safe design

[tex]\sigma _h <S_{yt}[/tex]

So 2.6 P <600

P<230.76 MPa

So the maximum pressure= 230.76 M Pa

Answer:

Whatever I do not care about the question.

Explanation:

It is a old question.

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