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A large rectangular tub is filled to a depth of 2.60 m with olive oil, which has density 915 kg/m3 . If the tub has length 5.00 m and width 3.00 m, calculate (a) the weight of the olive oil, (b) the force of air pressure on the sur- face of the oil, and (c) the pressure exerted upward by the bottom of the tub.

Respuesta :

Answer:

weight is 3.50 x 10^5 N

force is 1.52 * 10^6 N

pressure is 1.25 * 10^5 Pa

Explanation:

given data

Given data

depth = 2.60 m

density = 915 kg/m3

length = 5.00 m

width = 3.00 m

to find out

weight of the olive oil, force of air pressure and the pressure exerted upward

solution

we know density = mass / volume

mass = density* width *length *depth

mass = (915)(3)(5)(2.60)

mass = 3.57 x 10^4 Kg

so weight = mg = 3.57 x 10^4 (9.81) = 3.50 x 10^5 N

weight is 3.50 x 10^5 N

and

we know force = pressure * area

area = 3 *5 = 15 m²

and we know atmospheric Pressure is about 1.01 * 10^5 Pa

so force = 1.01 * 10^5 (15) = 1.52 x 10^6 N

force is 1.52 * 10^6 N

and

we know Fup - Fdown = Weight

so

Fup = 1.52 *  10^6 + 3.50 *  10^5

Fup = 1.87 * 10^6 N

so pressure = Fup / area

pressure =  1.87 * 10^6  / 15

pressure is 1.25 * 10^5 Pa

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