Respuesta :
Answer : The balanced chemical equation is,
[tex]2MnO_4^-(aq)+Mn(OH)_2(s)+4OH^-(aq)\rightarrow 3MnO_4^{2-}(aq)+2H_2O(l)[/tex]
The coefficient for [tex]OH^-[/tex] is, 4 and on reactant side of the equation [tex]OH^-(aq)[/tex] is present.
Explanation :
Rules for the balanced chemical equation in basic solution are :
- First we have to write into the two half-reactions.
- Now balance the main atoms in the reaction.
- Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
- If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
- If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion [tex](OH^-)[/tex] at that side where the less number of hydrogen are present.
- Now balance the charge.
The half reactions in the basic solution are :
Reduction : [tex]Mn(OH)_2(s)+1e^-\rightarrow MnO_4^{2-}(aq)[/tex] ......(1)
Oxidation : [tex]MnO_4^-(aq)+4OH^-(aq)\rightarrow MnO_4^{2-}(aq)+2H_2O(l)+2e^-[/tex].....(2)
Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.
The balanced chemical equation in a basic solution will be,
[tex]2MnO_4^-(aq)+Mn(OH)_2(s)+4OH^-(aq)\rightarrow 3MnO_4^{2-}(aq)+2H_2O(l)[/tex]
Thus, the coefficient for [tex]OH^-[/tex] is, 4 and on reactant side of the equation [tex]OH^-(aq)[/tex] is present.
