Answer:
Please let me know if your quadratic is [tex]y=-2(x+2)^2+2[/tex].
And if so your vertex is (-2,2) and your y-intercept is (0,-6)
Step-by-step explanation:
It says vertex so I'm thinking you meant [tex]y=-2(x+2)^2+2[/tex]. Please correct me if I'm wrong.
The vertex form of a quadratic is [tex]y=a(x-h)^2+k[/tex]. It is called that because it tells you the vertex (h,k).
So if you compare the two forms you should see -h=2 while k=2.
-h=2 implies h=-2.
So the vertex is (h,k)=(-2,2).
To find the y-intercept, set x=0 and find y.
[tex]y=-2(0+2)^2+2[/tex]
[tex]y=-2(2)^2+2[/tex]
[tex]y=-2(4)+2[/tex]
[tex]y=-8+2[/tex]
[tex]y=-6[/tex]
So the y-intercept is (0,-6).
