Answer:
[tex]\boxed{\text{1. y + 5 = -4(x - 3); \qquad 2. y - 8 = x + 1}}[/tex]
Step-by-step explanation:
Question 1
The point-slope formula for a straight line is
y – y₁ = m(x – x₁)
x₁ = 3; y₁ = -5; m = -4
Substitute the values
[tex]\boxed{\textbf{y + 5 = -4(x - 3)}}[/tex]
The diagram shows the graph of equation 1 (red) with slope -4 passing through (3,-5).
Question 2
x₁ = -1; y₁ = 8; m = 1
Substitute the values
[tex]\boxed{\textbf{y - 8 = x + 1}}[/tex]
The diagram shows the graph of equation 2 (green) with slope 1 passing through (-1,8).
