Answer:
81 lots of 5,000 square feet fits in the property.
Step-by-step explanation:
The first step is calculate the square feet of the minimum area:
[tex]50 \: feets \times 100 \: feet = 5,000 \:square \: feet[/tex]
Second, from the ten acres we subtract the 26,000 feets of roads:
[tex]1 \: acre = 60 \: feet \times 660\:feet = 43,560\:square\:feet\\43,560 \times 10 = 435,600\\435,600 - 26,000 = 409,600 \:square \: feet\:available[/tex]
Third, we divide the lot area over the available square feet
[tex]\frac{409,600}{5,000} = 81.92[/tex]
81 lots of 5,000 square feet fits in the property.
