Respuesta :

Answer:

True

Step-by-step explanation:

We can plug in and see.

If (3,0) is on the graph of P, then P(3) will evaluate to 0.

Let's try it:

P(3)=(3)^3-7(3)^2+15(3)-9

P(3)=27-7(9)+45-9

P(3)=27-63+45-9

P(3)=-36+45-9

P(3)=9-9

P(3)=0

Since P(3)=0, then (3,0) is an ordered pair of P.

Yes it is true that the point (3,0) lies on the graph of

P(x) = [tex]x^{3}-7x^{2} +15x-9[/tex].

What is an equation?

An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values.

Given equation

P(x) = [tex]x^{3}-7x^{2} +15x-9[/tex]

If (3,0) is on the graph of P, then P(3) will evaluate to 0.

Substitute x = 3 in the given equation

P(3) = [tex](3)^3-7(3)^2+15(3)-9[/tex]

P(3) = [tex]27-7(9)+45-9[/tex]

P(3) = [tex]27-63+45-9[/tex]

P(3) = 9-9

P(3) = 0

Since P(3)=0, then (3,0) is an ordered pair of P.

Yes it is true that the point (3,0) lies on the graph of

P(x) = [tex]x^{3}-7x^{2} +15x-9[/tex].

Find out more information about equation here

brainly.com/question/2263981

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