Respuesta :
Answer:
True
Step-by-step explanation:
We can plug in and see.
If (3,0) is on the graph of P, then P(3) will evaluate to 0.
Let's try it:
P(3)=(3)^3-7(3)^2+15(3)-9
P(3)=27-7(9)+45-9
P(3)=27-63+45-9
P(3)=-36+45-9
P(3)=9-9
P(3)=0
Since P(3)=0, then (3,0) is an ordered pair of P.
Yes it is true that the point (3,0) lies on the graph of
P(x) = [tex]x^{3}-7x^{2} +15x-9[/tex].
What is an equation?
An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values.
Given equation
P(x) = [tex]x^{3}-7x^{2} +15x-9[/tex]
If (3,0) is on the graph of P, then P(3) will evaluate to 0.
Substitute x = 3 in the given equation
P(3) = [tex](3)^3-7(3)^2+15(3)-9[/tex]
P(3) = [tex]27-7(9)+45-9[/tex]
P(3) = [tex]27-63+45-9[/tex]
P(3) = 9-9
P(3) = 0
Since P(3)=0, then (3,0) is an ordered pair of P.
Yes it is true that the point (3,0) lies on the graph of
P(x) = [tex]x^{3}-7x^{2} +15x-9[/tex].
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