Answer:
n = 9
Explanation:
Given parameters:
Molar mass of Na₂SO₄.nH₂O = 304.04gmol⁻¹
Solution
To find the hydration number n, we simply express atomic masses of the atoms in the compound as equal to the given molar mass.
Atomic mass of Na = 23g
S = 32g
O = 16g
H = 1g
Molar mass of the compound is evaluated as:
2(23) + 32 + 4(16) + n[2(1) + 16] = 304.04
46 + 32 + 64 + 18n = 304.04
142 + 18n = 304.04
18n = 304.04 - 142
18n = 162.04
n = 9
