contestada

The combustion of hexane is given by the following reaction. 2 C6H14 + 19 O2 12 CO2 + 14 H2O The enthalpy of reaction is −4163.0 kJ/mol. How much energy (in joules) will be released if 62.30 grams of hexane is burned. (Molar mass of hexane = 86.20 g/mol).

Respuesta :

luisongonz

Answer:

3'008,757.5 Joules

Explanation:

First, calculate the hexane (Hx) moles:

[tex]62.30g Hx \frac{1 mol Hx}{86.20 g Hx} =0.723 mol Hx[/tex]

Then, multiply the number of moles by the enthalpy of reaction (the enthalpy of reaction is given by mole of reactant):

[tex]0.723molHx*\frac{-4163.0kJ}{1molHx}=-3,008.76kJ[/tex]

Change to Joules:

[tex]-3,008.76kJ*\frac{1000J}{1kJ}=-3'008,757.5 J.[/tex]

It has negative sign due to its released energy, so the answer should be positive: 3'008,757.5 J

Otras preguntas