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A gas sample has a volume of 0.225 L with an unknown temperature. The same gas has a volume of 0.180 L when the temperature is 35 ∘C, with no change in the pressure or amount of gas. Part A What was the initial temperature, in degrees Celsius, of the gas?

Respuesta :

gilcarusolautaro

Answer:

The initial temperature of the gas was of T1= 112ºC .

Explanation:

T1= ?

T2= 35 ºC = 308.15 K

V1= 0.225 L

V2= 0.18 L

T2* V1 / V2 = T1

T1= 385.18 K = 112ºC