A jar contains 10 blue marbles, 6 red marbles, and 3 yellow marbles. Cindy picks two marbles at random, without replacement.

Which product gives the probability that both of Cindy's choices be red marbles?

A) 6/19 × 5/19
B) 6/19 × 6/19
C) 6/19 × 5/18
D) 6/19 × 6/18

There are 6 red marbles out of 10+6+3 = 19 total. So 6/19 is the probability of picking one red marble. If that marble is not replaced, then we have 6-1 = 5 red marbles left out of 19-1 = 18 total. The probability of picking another red is 5/18

We have 6/19 as the probability of picking red the first time, then 5/18 as the probability of picking another red marble. The first marble is not put back, and that marble is not replaced.

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In terms of math notation, we can say

A = event of picking red on the first selection

B = event of picking red on the second selection

P(A) = 6/19

P(B|A) = 5/18

P(A and B) = P(A)*P(B|A)

P(A and B) = 6/19 * 5/18

A jar contains 10 blue marbles, 6 red marbles, and 3 yellow marbles. Cindy picks two marbles at random, without replacement. Which product gives the probability that both of Cindy's choices be red marbles? A) 6/19 × 5/19 B) 6/19 × 6/19 C) 6/19 × 5/18 D) 6/19 × 6/18

Respuesta :

Answer: Choice C) 6/19 x 5/18

Otras preguntas

A jar contains 10 blue marbles, 6 red marbles, and 3 yellow marbles. Cindy picks two marbles at random, without replacement.

Which product gives the probability that both of Cindy's choices be red marbles?

A) 6/19 × 5/19
B) 6/19 × 6/19
C) 6/19 × 5/18
D) 6/19 × 6/18