Answer:
[tex]H'(-3,-18)\\\\J'(3,-9)\\\\K'(-15,-3)\\\\L'(15,-15)[/tex]
Step-by-step explanation:
We know the coordinates of the polygon HJKL:
H(-1,-6), J(1,-3), K(-5,-1), and L(5,-5)
We know that the polygon HJKL is dilated using the scale factor 3. This means that, to find the coordinates of the vertices of polygon H'J'K'L', we need to multiply the x-coordinate and the y-coordinate of each vertex by this scale factor.
Then:
[tex]H'=(-1(3),-6(3))=(-3,-18)\\\\J'=(1(3),-3(3))=(3,-9)\\\\K'=(-5(3),-1(3))=(-15,-3)\\\\L'=(5(3),-5(3))=(15,-15)[/tex]
