Answer:
2
Step-by-step explanation:
4x = 32 - x2 would be much clearer if written as 4x = 32 - x^2. Please use
" ^ " to indicate exponentiation.
Rewrite 4x = 32 - x^2 in the standard form of a quadratic: x^2 + 4x - 32
Then the coefficients are a = 1, b = 4 and c = -32.
Find the discriminant. It is b^2-4ac.
Here, b^2-4ac = 4^2 - 4(1)(-32), or 16 + 128, or 144.
Because the discriminant is positive, we know immediately that this quadratic has two real, unequal roots.
So, the answer to this question is "the graph of 4x = 32 - x^2 cross the x-axis in two places."
Answer:
How many times does the graph of 4x = 32 - x2 cross the x-axis?
2
What are the solutions to the equation?
✔ 4, -8
Step-by-step explanation:
