[tex]\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{16}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{16-9}{-3-1}\implies \cfrac{7}{-4}\implies -\cfrac{7}{4}[/tex]
Answer:
[tex]\huge\boxed{-\frac{7}{4}}[/tex]
Step-by-step explanation:
Slope formula
[tex]\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]\displaystyle\frac{16-9}{(-3)-1}=\frac{7}{-4}=-\frac{7}{4}[/tex]
Therefore, the slope is [tex]\displaystyle -\frac{7}{4}[/tex], [tex]\displaystyle -\frac{7}{4}[/tex] is the correct answer.
