Answer:
[tex](3x+5)[/tex]
Step-by-step explanation:
The given polynomial expression is:[tex]6x^2+x-15[/tex]
We compare to [tex]ax^2+bx+c[/tex] and have a=6,b=1,c=-15
The product [tex]ac=6\times -15=-90[/tex]
Two factors of -90 that sums to 1 are -9 and 10
We split the middle term to get:
[tex]6x^2+10x-9x-15[/tex]
[tex]2x(3x+5)-3(3x+5)[/tex]
[tex](3x+5)(2x-3)[/tex]
Therefore the other factor is:
[tex](3x+5)[/tex]
