Answer: Hello there!
Well, the square root is the inverse function of the square potential.
This is if you have [tex](\sqrt{x} )^{2} = x[/tex] and [tex]\sqrt{x^{2} } = +-x[/tex]
A interesting part of the square root is that (-4)*(-4) = 16, and 4*4 = 16, so the solutions for [tex]\sqrt{16}[/tex] are -4 and 4. For this is that you see a +- symbol in the second equation.
Now, if you have the number [tex](a*b)^{2}[/tex]
Now, we put this inside a square root: [tex]\sqrt{(a*b)^{2} } = +-a*b[/tex]
So the solutions for the square root of (a*b)^2 are a*b and - a*b.
