The circle below is centered at the point (3,1) and has a radius length of 2.What is its equation

Answer:
C. [tex](x-3)^2+(y-1)^2=2^2[/tex]
Step-by-step explanation:
The standard equation of a circle, given the radius r units and center (h,k) is given by:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
From the question, we have the center of the circle to be (3,1) and the radius is 2 units.
We substitute the center and radius of the circle into the equation to get:
[tex](x-3)^2+(y-1)^2=2^2[/tex]
The correct answer is C