Answer:
The diagonal of this rectangle is 41 units.
Step-by-step explanation:
The relationship between the length and width of a rectangle and the diagonal is given by the Pythagorean identity:
[tex]d=\sqrt{l^2+w^2}[/tex]
From, the given question, the rectangle has a width of 9 units and a length of 40 units.
We substitute the width and length of the rectangle into the equation to get:
[tex]d=\sqrt{40^2+9^2}[/tex]
[tex]d=\sqrt{1600+81}[/tex]
[tex]d=\sqrt{1681}[/tex]
[tex]d=41[/tex] units.
