Answer:
The sum is a binomial with a degree of 6
Step-by-step explanation:
we have
[tex](3x^{2}y^{2}-2xy^{5})+(-3x^{2}y^{2}+3x^{4}y)[/tex]
Group terms that contain the same variable
[tex](3x^{2}y^{2}-3x^{2}y^{2})-2xy^{5}+3x^{4}y[/tex]
[tex]0-2xy^{5}+3x^{4}y[/tex]
[tex]-2xy^{5}+3x^{4}y[/tex]
The sum is a binomial ( two terms) with a degree of 6
[tex]-2xy^{5}[/tex] has a degree of 6 (x has an exponent of 1, y has 5, and 1+5=6)
The sum of the polynomial is a binomial with a degree of 6. The correct option is D) and this can be determined by using arithmetic operations.
Given :
Polynomials -- [tex]3x^2y^2-2xy^5[/tex] and [tex]-3x^2y^2+3x^4y[/tex]
The following steps can be used to determine the sum of the given polynomials:
Step 1 - Write the sum of the given polynomials.
[tex]3x^2y^2-2xy^5-3x^2y^2+3x^4y[/tex]
Step 2 - Subtract [tex]3x^2y^2[/tex] from [tex]3x^2y^2[/tex] in the above expression.
[tex]-2xy^5+3x^4y[/tex]
The above expression cannot be further simplified. Therefore, this is the final expression of the sum of the given polynomials.
The sum of the polynomial is a binomial with a degree of 6. Therefore, the correct option is D).
For more information, refer to the link given below:
https://brainly.com/question/1957976
