A line passes through the point (-6,2) and has a slope of -5/2 ,Write an equation in pint slope form for this line

Answer:
see explanation
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
here m = - [tex]\frac{5}{2}[/tex] and (a, b) = (- 6, 2), so
y - 2 = - [tex]\frac{5}{2}[/tex] (x - (- 6)), that is
y - 2 = - [tex]\frac{5}{2}[/tex] (x + 6) ← in point- slope form
An equation in point slope form for this line y - 2 = -5/2 (x + 6) .
The point slope form of a straight line in geometry is used to represent the equation of a straight line using its slope 'm' and a point(x, y) that lies on the given line.
equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Now, m = - 5/2
and (a, b) = (- 6, 2)
So, the equation of line be
y-2= -5/2 (x+6)
Hence,
y - 2 = -5/2 (x + 6) in point- slope form.
Learn more about point- slope form here:
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