First you must distribute the 2x to the numbers inside the parentheses
(2x * x) + (2x * -1) = 3
[tex]2x^{2}[/tex] - 2x = 3
To make this a quadratic equation you can solve bring the 3 over to the left side of the equation by subtracting it to both sides
[tex]2x^{2}[/tex] - 2x - 3 = 0
Use the quadratic equation to solve this (image of the quadratic equation is below)
Remember that quadratic functions are set up like so:
[tex]ax^{2} +bx +c = 0[/tex]
That means that in this equation...
a = 2
b = -2
c = -3
^^^Plug these numbers into the quadratic equation and solve...
[tex]\frac{2+/-\sqrt{(-2)^{2}-4(2)(-3)}}{2(2)}[/tex]
[tex]\frac{2 +/-\sqrt{4+24}}{4}[/tex]
[tex]\frac{2+/-\sqrt{28} }{4}[/tex]
[tex]\frac{2+/-2\sqrt{7} }{4}[/tex]
[tex]\frac{1+/-\sqrt{7} }{2}[/tex]
Keep in mind that +/- is ±
[tex]\frac{1+\sqrt{7} }{2}[/tex]
[tex]\frac{1-\sqrt{7} }{2}[/tex]
^^^Exact answers
Approximations:
1.823
-0.823
Hope this helped!
~Just a girl in love with Shawn Mendes
