find the perimeter of the following shape, round to the nearest tenth

Answer: you take the slope of the lines rise over run and add together
Step-by-step explanation:
The perimeter of the figure is:
17.9 units
We know that the perimeter of the figure is the sum of all the side lengths of a figure i.e. it is the sum of the distance around a figure.
In the given figure the perimeter of the figure is:
Length AB+Length BC+Length CD+Length AD
Now from the figure we see that:
A is located at (-3,5)
B is at (1,7)
C is located at (3,3)
and D at (-1,1)
Hence, by using distance formula we get:
[tex]AB=\sqrt{(1-(-3))^2+(7-5)^2}\\\\\\AB=\sqrt{4^2+2^2}\\\\\\AB=\sqrt{20}\ units[/tex]
[tex]BC=\sqrt{(3-1)^2+(3-7)^2}\\\\\\BC=\sqrt{2^2+4^2}\\\\\\BC=\sqrt{20}\ units[/tex]
[tex]CD=\sqrt{(-1-3)^2+(1-3)^2}\\\\\\CD=\sqrt{4^2+2^2}\\\\\\CD=\sqrt{20}\ units[/tex]
and
[tex]AD=\sqrt{(-1-(-3))^2+(1-5)^2}\\\\\\AD=\sqrt{20}\ units[/tex]
Hence, we get perimeter of figure is:
[tex]=\sqrt{20}+\sqrt{20}+\sqrt{20}+\sqrt{20}\\\\=4\times \sqrt{20}\\\\\\=8\sqrt{5}\\\\\\=17.88854\ units[/tex]
Hence, to the nearest tenth we have:
Perimeter=17.9 units