Answer:
4x - 3y -18 = 0 or y = 4x/3 - 6
Step-by-step explanation:
We will have to find the slope of the line first
The formula for slope:
[tex]m =\frac{y_{2}- y_{1} }{x_{2} -x_{1} } \\m= \frac{-2-2}{3-6}\\ =\frac{-4}{-3}\\ =\frac{4}{3}[/tex]
The standard form of equation of a line is:
y = mx + b
We know m,
So the equation will be:
[tex]y= \frac{4}{3}x+b[/tex]
We have to find the value of b, for that we will put any one of the point in the equation
So, putting (6,2)
2 = 4/3 * 6 + b
2 = 8 +b
b = -6
Putting the value of m and b in the standard form of equation of line,
[tex]y = mx + b\\y = \frac{4}{3}x+(-6)\\y = \frac{4}{3} x - 6\\Multiplying\ both\ sides\ by\ 3\\3y = 4x - 18\\4x - 3y -18 = 0[/tex] ..
