Answer:
the answer is 126!
Step-by-step explanation:
i worked it out myself, and got it correct! have a great day :)
There are 126 ways can a committee of 4 be chosen from a group of 9 people, the correct option is B.
The solution is obtained through a combination where we choose "r of n", where r is the amount of things we choose and n the total number of things that can be chosen.
The combinations form uses factorial numbers. This is the formula:
[tex]\rm ^nC_r=\dfrac{n!}{(n-r)!r!}[/tex]
Where the value of n is 9 and r is 4.
The number of ways can a committee of 4 be chosen from a group of 9 people is;
[tex]\rm ^nC_r=\dfrac{n!}{(n-r)!r!}\\\\\rm ^9C_4=\dfrac{9!}{(9-4)!4!}\\\\ ^9C_4=\dfrac{9!}{5!4!}\\\\ ^9C_4=\dfrac{9\times 8 \times 7 \times 6 \times 5!}{5!\times 4\times 3\times 2\times 1}\\\\ ^9C_4=\dfrac{3024}{24}\\\\ ^9C_4=126[/tex]
Hence, there are 126 ways can a committee of 4 be chosen from a group of 9 people, the correct option is B.
Learn more about combination here;
https://brainly.com/question/3929817
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