Answer:
[tex]x=-2[/tex].
Step-by-step explanation:
The rational function given to us is:
[tex]f(x)=\frac{x^2-4x-12}{x+2}[/tex]
We can factor the numerator to obtain
[tex]f(x)=\frac{(x+2)(x-6)}{x+2}[/tex]
We can see clearly that, there is a linear common factor of both the numerator and the denominator.
This factor is [tex](x+2)[/tex].
This implies that, there is a removable discontinuity at [tex]x=-2[/tex].
Therefore, there is a removable discontinuity at [tex]x=-2[/tex].
