ahemnotalking
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How do I solve this?

A football punted upward has a trajectory given by the equation y = 48x − 16x2, where y represents the football's height x seconds after it has been kicked. What is the maximum height, in feet, attained by the ball?

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Respuesta :

musiclover10045

The maximum happens at x = -b/2a

x = -48/2(-16) = 3/2

Now replace x in the equation and solve for y:

y = 48(3/2) - 16(3/2)^2

y =  -72 - 36

y = 36

The maximum height is 36 feet.

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