-The equation is actually
5x^2 -2x+1=0;
-The discriminant is b^2 -4ac=4-4•5•1=4-20=-16
-this means that the equation has no real number solutions
Answer:
The discriminant is equal to −16, which means the equation has no real number solutions.
Step-by-step explanation:
[tex]\text{Given the quadratic equation }-1=5x^2-2x[/tex]
we have to find the number of real number solutions the equation has.
The equation is
[tex]5x^2-2x+1=0[/tex]
[tex]\text{Comparing above equation }ax^2+bx+c=0[/tex]
a=5, b=-2, c=1
To find number of real solutions we have to find the discriminant
[tex]D=b^2-4ac[/tex]
[tex]D=(-2)^2-4(5)(1)[/tex]
[tex]D=4-20=-16[/tex]
The value of discriminant is -16<0
Hence, the equation has no real roots.
Hence, option 1 is correct
