Answer:
44 and 46
Step-by-step explanation:
Let
x,x+2-----> the two consecutive positive even integers
we know that
[tex](x+x+2)^{2}=x^{2}+(x+2)^{2} +4,048[/tex]
Solve for x
[tex](x+x+2)^{2}=x^{2}+(x+2)^{2} +4,048\\ \\4x^{2} +8x+4=x^{2}+x^{2} +4x+4+4,048\\ \\2x^{2} +4x-4,048=0[/tex]
Solve the quadratic equation by graphing
The solution is x=44
see the attached figure
therefore
the numbers are
x=44
x+2=46
