Respuesta :

gmany

Answer:

[tex]\large\boxed{_6P_2=30}[/tex]

Step-by-step explanation:

[tex]_nP_k=\dfrac{n!}{(n-k)!}\\\\n!=1\cdot2\cdot3\cdot...\cdot n\\======================\\\\_6P_2=\dfrac{6!}{(6-2)!}=\dfrac{6!}{4!}=\dfrac{4!\cdot5\cdot6}{4!}\\\\\text{cancel}\ 4!\\\\=5\cdot6=30[/tex]

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