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Under certain circumstances, carbon dioxide, CO2(g), can be made to react with hydrogen gas, H2(g), to produce methane, CH4(g), and water vapor, H2O(g): CO2(g)+4H2(g)→CH4(g)+2H2O(g)Part A How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas? Express your answer with the appropriate units. For example, write the unit moles as mol.Part B How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 42.1 moles of water vapor? Express your answer with the appropriate units. For example, write the unit moles as mol.

Respuesta :

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These are two questions and two answers.

Answers:

  • Part A: 59.6 mol CH₄

  • Part B: 84.2 mol H₂ (g)

Explanation:

1) Balanced chemical equation (given):

  • CO₂(g) + 4H₂(g)  → CH₄(g) + 2H₂O(g)

2) Part A: How many moles of methane are produced when 59.6 moles of carbon dioxide gas react with excess hydrogen gas?

a) Mole ratios:

  • 1 moles CO₂(g) : 1 mole CH₄(g)

b) Proportion:

  • 1 moles CO₂ / 1 mol CH₄ = 59.6 moles CO₂ / x

         ⇒ x = 59.6 mol CH₄ ← answer

3) Part B How many moles of hydrogen gas would be needed to react with excess carbon dioxide to produce 42.1 moles of water vapor?

a) Mole ratios:

  • 4 mol H₂(g)  : 2 mol H₂O(g)

b) Proportion:

  • 4 mol H₂ / 2 mol H₂O = x / 42.1 mol H₂O

         ⇒ x = 42.1 × 4 / 2 moles CH₄ = 84.2 mol H₂ (g) ← answer

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